Person:Jane Hinde (1)

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Jane Hinde
b.9 Aug 1845 Ince, Cheshire
d.17 Nov 1902 Iowa, United States
m. 1 Jul 1834
  1. Richard Hinde1835 -
  2. Thomas Hinde1836 - 1890
  3. Hannah Hinde1838 - 1864
  4. Alice Hinde1841 -
  5. John Hinde1843 - 1919
  6. Jane Hinde1845 - 1902
  7. Eliza Hinde1847 - 1853
  8. Mary Hinde1850 -
m. 30 Jan 1868
  1. Herbert Thomas Greenley1880 - 1963
Facts and Events
Name Jane Hinde
Gender Female
Birth? 9 Aug 1845 Ince, Cheshire
Marriage 30 Jan 1868 Rickardsville, Dubuque, Iowa, United Statesto Thomas Marwood Greenley
Death? 17 Nov 1902 Iowa, United States